Here is how the game goes. We go from 1 to 1000 using our posts. The posts have to include a number between 1 - 1000 in context, example...
"This game is so simple a 1 year old could play it"OR / AND"I was so bored I drank12 cans of pepsi and freaked out"
In addition all numbers from 1 - 1000 must be posted in accending order.
This game is so simple a 1 year old could play it.
ps. remember people this game is all about fun. post interesting and creative posts whilst doing this and it will be great
This is possibly the strangest thread I have seen posted at 2 AM.
According to the forum time, at least.
Hey, I got post 3
So.....just what are we doing this 4 anyway
So...i wonder if this thread will make 1000 or will it die here at number four..or is that five...
Damn wish i could count!! Where is Count Dracula when ya need him....
1,2,3,4,5.....6,7,8,9,10....11....errmmmm 76????
Five is between 4 and 6 and is the third prime number, after 2 and 3, and before 7. Because it can be written as 2^(2^1)+1, five is classified as a Fermat prime. 5 is the third Sophie Germain prime, the first safe prime, and the third Mersenne prime exponent. Five is the first Wilson prime and the third factorial prime, also an alternating factorial. Five is the first Good prime. It is an Eisenstein prime with no imaginary part and real part of the form 3n − 1. It is also the only number that is part of more than one pair of twin primes.
Five is conjectured to be the only odd untouchable number and if this is the case then five will be the only odd prime number that is not the base of an aliquot tree.
The number 5 is the 5th Fibonacci number, being 2 plus 3. 5 is also a Pell number and a Markov number, appearing in solutions to the Markov Diophantine equation: (1, 2, 5), (1, 5, 13), (2, 5, 29), (5, 13, 194), (5, 29, 433), ... (A030452 lists Markov numbers that appear in solutions where one of the other two terms is 5). Whereas 5 is unique in the Fibonacci sequence, in the Perrin sequence 5 is both the fifth and sixth Perrin numbers.
5 and 6 form a Ruth-Aaron pair under either definition.
There are five solutions to Znám's problem of length 6.
Five is the second Sierpinski number of the first kind, and can be written as S2=(2^2)+1
While polynomial equations of degree 4 and below can be solved with radicals, equations of degree 5 and higher cannot generally be so solved. This is the Abel-Ruffini theorem. This is related to the fact that the symmetric group Sn is a solvable group for n ≤ 4 and not solvable for n ≥ 5.
While all graphs with 4 or fewer vertices are planar, there exists a graph with 5 vertices which is not planar: K5, the complete graph with 5 vertices.
Five is also the number of Platonic solids.
A polygon with five sides is a pentagon. Figurate numbers representing pentagons (including five) are called pentagonal numbers. Five is also a square pyramidal number.
Five is the only prime number to end in the digit 5, because all other numbers written with a 5 in the ones-place under the decimal system are multiples of five. As a consequence of this, 5 is in base 10 a 1-automorphic number.
Vulgar fractions with 5 or 2 in the denominator do not yield infinite decimal expansions, as is the case with most primes, because they are prime factors of ten, the base. When written in the decimal system, all multiples of 5 will end in either 5 or 0.
There are five Exceptional Lie groups.
Wow, that last post had me doing math for 6 hours, and I didnt even figure half that out.
Alright then mister luckymann can you tell me about number 7 then?
I say this has had a good start.
To l8 we just skipped to 9
i guess it'll get pretty boring to name a number in every post, unless you get drunk, then u can talk about drinking 15 beer
Im very sad the nubmer only goes til 1.000
otherwise i couldve named my Member Number
Member No.2,988,115
wee
limx->5 (x2-25)/(x-5)
I just finished a nice SP game with seventy-eight planets and nine AI + me.
Holy cow, the game lasted for a little over 11 hours.
limx->7 (2x3-7x2-64x+105)/(x2-2x-35)
edit: aw... you beat me to 11.... now i gotta make up another
limx->8 (2x4-30x3+104x2+120x-448)/(x3-13x2+26x+112)
Enjoy
Sorry, but your second attempt is incorrect L'hopital's rule is only applicable if the limits of both the numerator and denominator are zero (or infinity). In your limit, the limit of the denominator evaluates to a finite non-zero number while the limit of the numerator is just zero. Therefore your limit simply evaluates to zero.
So here is a valid one:
6/(πi) ∲C(1/z)dz
(the circle denotes that this is a contour integral, and take C to be the unit circle in the complex plane)
I might be misunderstanding you, but it seems to evaluate to 0/0.
(2x4-30x3+104x2+120x-448)/(x3-13x2+26x+112)
(2*4096-30*512+104*64+120*8-448)/(512-13*64+26*8+112)
(8192-15360+6656+960-448)/(512-832+208+112)
(-7168+7168)/(-320+320)
0/0
PS:
limx->8 (2x2-18x+16)/(x-8)
I'm sorry, on closer inspection it seems that I mentally inserted a negative sign where it didn't belong. I'm going to go bang my head on the wall 15 times as penance.
I'm reply 16.
Have not done that much math since I was 17. Damn Im old. (30)
Or was it 18 years old
i just spent 19 minutes trying to figure the math out, and its giving me a headache
I spent 20 seconds looking at the math.
Then on second 21 decided to just say...screw that.
And on second 22, decided to do better things with my time.
Let's start a pool on how many days it will take to hit post one thousand. I'm putting my $$$$$ on 23 days.
2 beer 7$
three margaritas $15
four jello shots $20
Taking home the girl
who drank all of the above....
Priceless
=]]]]]]]]]]]]]]]]]
TheSpydyr
Member No.3,125,868
There are many great features available to you once you register, including:
Sign in or Create Account